CH 39 #9 - 39.9: a) photon hc E so electron hc E (6.626 10...

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39.9: a) photon nm 0 . 62 V) e J 10 602 . 1 ( ) eV 0 . 20 ( ) s m 10 998 . 2 ( ) s J 10 626 . 6 ( λ so λ 19 8 34 = × × × = = = - - E hc hc E electron = × × = = = - - V) e J 10 602 . 1 ( eV) 0 . 20 ( ) kg 10 109 . 9 ( 2 2 so ) 2 ( 19 31 2 mE p m p E s m kg 10 416 . 2 24 × - nm 274 . 0 λ = = p h b) photon eV 96 . 4 J 10 946 . 7 λ 19 = × = = - hc E electron s m kg 10 650 . 2 λ so λ 27 × = = = - h p p h eV 10 41 . 2 J 10 856 . 3 ) 2 ( 5 24 2 - - × = × = = m p E c) You should use a probe of wavelength approximately 250 nm. An electron with
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This homework help was uploaded on 04/02/2008 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.

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