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Unformatted text preview: 39.11: a) = 0.10 nm p = mv = h so v = h (m) = 7.3 10 6 m s b) E = 1 mv 2 = 150 eV 2 c) E = hc = 12 keV d)The electron is a better probe because for the same it has less energy and is less damaging to the structure being probed. ...
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This homework help was uploaded on 04/02/2008 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.
- Spring '08