CH 39 #27 - 39.27: a) We recall λ = h = p potential is...

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Unformatted text preview: 39.27: a) We recall λ = h = p potential is just E = e∆V h (6.63 × 10 −34 J ⋅ s) ⇒ λe = = 2m∆V 2(9.11 × 10 −31 kg ) (1.60 × 10 −19 C) (800 V) ⇒ λ e = 4.34 × 10 −11 m. b) For a proton, all that changes is the mass, so me 9.11 × 10 −31 kg λp = λe = . 4.34 × 10 −11 m mp 1.67 × 10 −27 kg h . But the energy of an electron accelerated through a 2mE ( ) ⇒ λ e = 1.01 × 10 −12 m. ...
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