CH 39 #48 - 39.48: a) (6.626 10 -34 J s) = 2.1 10 -20 kg m...

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Unformatted text preview: 39.48: a) (6.626 10 -34 J s) = 2.1 10 -20 kg m s. -15 2 (5.0 10 m) b) K = ( pc) 2 + (mc 2 ) 2 - mc 2 = 1.3 10 -13 J = 0.82 MeV. c)The result of part (b), about 1 MeV = 1 10 6 eV , is many orders of magnitude larger than the potential energy of an electron in a hydrogen atom. ...
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