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Algebra Practice 1 solutions

# Algebra Practice 1 solutions - Answer Key Algebra more...

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Answer Key Algebra more practice Answer Key Directions: Show all work on a separate piece of paper. Place your final answer on this sheet. 1. Given 1 3 ) ( - = x x g a. Evaluate and simplify completely i) ) 2 ( - g = -1 ii) ) 0 ( g = -3 iii) ) 1 ( g = undefined iv) ) 4 ( g = 1 v) ) 3 ( + x g = 2 3 + x b. Solve algebraically for exact x i) 5 ) ( = x g ii) 4 ) 2 ( = + x g iii) 4 2 ) ( = + x g x = 5 8 x = 25 . 0 - x = 5 . 2 2. Simply the difference quotient for the following functions [different quotient ( 29 ( 29 h x f h x f - + ] a) ( 29 3 2 2 + + = x x x f ( 29 ( 29 h x f h x f - + = h x + + 2 2 b) ( 29 5 3 - = x x f ( 29 ( 29 h x f h x f - + = 2 2 3 3 h x xh + + c) ( 29 x x f 4 = ( 29 ( 29 h x f h x f - + = ) ( 4 h x x + - 3. Simplify the following completely with a common denominator. Your final answer will not contain any negative exponents. a) x x x x 2 2 5 1 4 + - - = ( 29 1 2 2 3 3 2 - + + x x x x b) ( 29 ( 29 2 4 2 2 - + + x x b b = ( 29 2 3 2 1 - + x b or ( 29 ( 29 x b b 3 2 2 2 + + c) 3 2 3 2 1 + + + + t t t = 3 7 4 + + t t d) ( 29 ( 29 ( 29 2 2 2 1 2 2 1 1 + - + x x x x x = ( 29 2 2 2 1 1 3 + + - x x e) 5 3 5 2 - - + x x = ( 29 25 25 2 - + - x x f) ( 29 ( 29 2 2 2 2 4 2 1 2 1 + + - + - z z z z = ( 29 2 3 2 8 2 + + z z or ( 29 ( 29 2 3 2 4 2 + + z z g) 1 1 3 3 + + n n n n a a = a 3 h) x x e e - 1 = e i) ( 29 ( 29 ( 29 4 3 3 3 2 3

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