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Using a Quadratic Equation Problems A ball is thrown vertically upward from the top of a building 112 feet tall with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s (t) = 112 + 96t - 16t 2 Complete the table and discuss the interpretation of each point. t s(t) Interpretation 0 0 At zero seconds (t) the ball was at its original height of 112ft s(t) (0,112) 0.5 156 At 0.5 seconds the ball will reach the height of 156 ft (0.5,156) 1 196 At 1 second the ball has reached a height of 192 ft (1,192) 2 240 At 2 seconds the ball has reached a height of 240 ft -0.122 5 100 Since this is a Parabola graph, the ball at 100 ft will have two different y coordinates For the ball to reach 100 ft it will take -0.1225 seconds. This shows that if the ball was never thrown but dropped instead it would take 0.1225 to drop 12 ft 6.122 5 100 Since this is a Parabola graph, the ball at 100 ft will have two different y coordinates For the ball to reach 100 ft after being thrown upwards it will take 6.1225 seconds.

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