{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

solution_assignment5

solution_assignment5 - Miami filament ataxia 1.D12 2.003...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Miami filament ataxia: 1 .D12 2 .003 3 .06? 4 .2fl2 Total .234 min. Narmal time {.284} {1.135} .298 mianiece Standard time = .298 (1.2fl} z .358 min.fpiece . .353 min. hr. _ . Placesfhour = 1ft PC 1 [ED min.) — 163 Elecesfhr. —-— Std. Laborflfifl pas. = {%1 {1—213} = $2.93 35.? 9min - 1hr. I: pass. Std. hrleflD pcs. r 1 =59? hrsJC pea. 2. a} A plot of the data shows a cyclic pattern that is generally level and regular. -11 Month -n--mnn Demand mmmnm-m_ 12 9? h} The moving average method would tend to give a forecasted value that always "lagged" the actual demand pattern. The exponentially weighted moving average method would do better. but would still tend to lag. A single regression equation fitted to the entire set of data would simply give a constant forecast of approximately 93 units per month. However, straight line segments could be fitted to each portion of the demand pattern, and this would give fairly good results. In fact. straight lines can be fitted 'hv eye" to each portion of the plotted data and extended into the future. ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern