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# solution1 - solution1 Page 1 of 11 LS through hw7 Answers...

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solution1.doc Page 1 of 11 LS through hw7 3/06/06 Answers assignment 1 Moran and Shapiro text problems. 1.2) drawings of system required. No numeric answers 1.12) a) 9.5m/s 2 b). 98.1N 1.21) 2 18.4 ft s - 1.31) 3 2 2.905 V m = 1.37) 14.379lbf/in 2 1.39) 2 .3944 lbf in 1.40 . . 1.2766 2.6766 abs b abs a P bar P bar = = 2.2) 97.8kJ 2.9) 210kJ 2.16) 2 11.23 m V s = 2.23) a). n=.90887 b). W= -.2163Btu c). W refrigerant ≈ -.2148Btu 2.25) 3 2 0.02 V m = 2.40) Work done on bar= -1.963J Numeric Answers for assignment 2 2.25 3 2 0.02 V m = 2.26 2 44.85 P psi = 2.29 80.47 W kJ =

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solution1.doc Page 2 of 11 2.37 1.1 1.07 0.03 2.2 2.14 electric shaft net electric shaft W kW W kW W kW W kWhr W kWhr = - = = - = - = 2.49 5607 Btu hr 2.55 5.4 Q kJ = - 2.56 2 260 kJ u kg = 2.58 23 23 75.21 687.8 W Btu Q Btu = = Homework 3: answers: 2.64a. 3 ).3 ) 36 ) 18 m a kg b W kJ kJ c U kg = - Δ = 2.67 283.6 Q Btu = 2.70 ). 112.6 ). 68.89 ). 131.39 gas a P kPa b W J c Q J = = = 2.74 done in class no answer required. 2.78 .33 33% η = = 3.2a. 2 phase liquid vapor mixture
solution1.doc Page 3 of 11 b. superheated vapor c. subcooled compressed liquid d. superheated vapor 3.9a). H 2 O x=.933 (nearly all vapor) b).propane x=0 (saturated liquid) c). R134a x=.524 d). ammonia x=.804 3.16)P=P sat =85.79psia T=T sat =70F 3.24)a). T a =140C b). x 2 =.1480 c). m=1.972kg d). V f2 =.00203m 3 Homework 4: 3.40, 3.42, 3.48, 3.57, 3.61 3.70, 3.74, 3.78, 3.84, 3.81, 3.93, 3.97 Homework 4: 3.40 Graph required. no numeric answer 3.42, 434.59kJ/kg 3.48, Q=175.1kJ 3.57, 3 .5006

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solution1 - solution1 Page 1 of 11 LS through hw7 Answers...

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