hw1_sol

hw1_sol - HW1 Answer Key 8-2. The number of observation n =...

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HW1 Answer Key 8-2. The number of observation n = 64 The number of intervals 8 n == Starting point = 32.0, Ending point = 38.0 The width of each interval is (38-32)/8 = 0.75 Class Interval Frequency 32 = x < 32.75 4 32.75 = < 33.5 5 33.5 = < 34.25 14 34.25 = < 35 16 35 = < 35.75 12 35.75 = < 36.5 4 36.5 = < 37.25 5 37.25 = < 38 4 37.625 36.875 36.125 35.375 34.625 33.875 33.125 32.375 15 10 5 0 C1 Frequency 4 5 4 12 16 14 5 4 8-2 Histogram Properties of the data: Shape: Unimodal (perhaps bimodal if you identify a secondary mode at ~37) Approximately Symmetric (This depends on how you define your intervals. Different selections can lead to graphs with different shape.) Location: ~34 Spread: ~6
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8-12 a) Stem-and-leaf plot N = 64 Leaf Unit = 0.10 6 32 156789 17 33 11456666688 (22) 34 0111223355666667777779 25 35 00111234456789 11 36 246888 5 37 13689 b) n = 64 1 . 2225 = x 77476 2 = x 834 . 1 63 64 ) 1 . 2225 ( 77476 2 2 = - = s s = 1.35 77 . 34 64 1 , 2225 = = x d) 65 . 34 2 7 . 34 6 . 34 2 ~ 33 32 5 . ) 2 1 64 ( = + = + = = = + x x x x x 8 . 33 2 8 . 33 8 . 33 2 1 17 16 25 . ) 4 1 ( = + = + = = = + x x x x Q 45 . 35 2 5 . 35 4 . 35 2 3 49 48 75 . 48 ) 4 ) 1 64 ( 3 ( = + = + = = = + x x x x Q e) IQR = Q3-Q1 = 35.45-33.8 = 1.65
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2. There is no correct answer to this question, only consistent and inconsistent answers. You should begin by defining the population.
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hw1_sol - HW1 Answer Key 8-2. The number of observation n =...

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