Homework5_Solution

Homework5_Solution - kA qL T T L T T kA q + = -= 2 1 2 1...

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BAEN-366 SPRING/09 Homework #5 Problem 1 Surface 1: ( 29 ( 29 ( 29 2 1 2 1 1 2 1 1 2 1 1 1 , 1 6 . 40076 03846 . 0 2 2 50 80150 15 . 0 3 . 0 1603 50 T T T T T T T T L T T k T T h q q cond conv + = - = - - = - - = - = Surface 2: ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 4 2 8 2 2 2 4 2 8 2 4 2 8 2 2 2 4 4 2 8 2 2 2 4 4 2 8 2 2 2 4 4 2 8 2 2 1 4 4 2 2 , 2 2 2 1 10 536 . 4 923 . 11 32 . 6420 07692 . 0 2 10 536 . 4 10 72 . 357 2980 6 . 3082 72 . 357 10 536 . 4 2980 10 2 07692 . 0 6 . 3082 298 10 536 . 4 2980 10 03846 . 0 3 . 1541 2 298 10 67 . 5 8 . 0 298 10 6 . 40076 03846 . 0 2 298 10 67 . 5 8 . 0 298 10 2 T x T T T T x T T x T T T T x T T T T x T T T T x T T T T T T T h L T T k q q q sur rad conv cond - - - - - - + = - + + = + + - + - = - + - + - = - + - + - = - + - + - = - - + - = - + = εσ Solving with calculator: K T 05 . 420 2 = And substituting for T 1 : ( 29 K T T 46 . 1557 420 6 . 40076 03846 . 0 1 1 = + =
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Problem 2 (1.10)
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Unformatted text preview: kA qL T T L T T kA q + = -= 2 1 2 1 For aluminum: ( 29 ( 29 ( 29 ( 29 C m m W C T mK W 39 . 110 4 2 . 240 005 . 600 110 2 1 = + = For copper: ( 29 ( 29 ( 29 ( 29 C m m W C T mK W 25 . 110 4 2 . 390 005 . 600 110 2 1 = + =...
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Homework5_Solution - kA qL T T L T T kA q + = -= 2 1 2 1...

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