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Question: SCalcCC2 7.4.02.
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Section 7.4 (Homework)
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Exponential Growth and Decay
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Question: SCalcCC2 7.4.06.
A common inhabitant of human intestines is the bacterium
Escherichia coli
. A cell of this
bacterium in a nutrientbroth medium divides into two cells every 20 minutes. The initial
population of a culture is 60 cells.
(a) Find the relative growth rate.
k
=
2.079
(b) Find an expression for the number of cells after
t
hours.
P
(
t
) =
(c) Find the number of cells after 8 hours.
1
billion cells
(d) Find the rate of growth after 8 hours.
2.079
billion cells per hour
(e) When will the population reach 20000 cells?
2.806
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This note was uploaded on 06/24/2009 for the course MA 241 taught by Professor Mccollum during the Spring '08 term at N.C. State.
 Spring '08
 Mccollum

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