hw4_answers

hw4_answers - Instructor Prof Doyoon Kim TA Diogo Bessam...

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Unformatted text preview: Instructor: Prof. Doyoon Kim TA: Diogo Bessam Please, during (and only during) Fall 2008, report any typo/error you may nd directly to Diogo Bessam ([email protected]) 3.5.22 3.5.26 4.1.18 HW4 answers, math118, 2008 r = 1 inches, h = 4 inches 4 + 5 2/2cm and 8 + 5 2 cm (a) x6 z 3 /y 9 (b) x1/2 z 2/3 y 1/3 4.1.28 (a) (b) (c) (d) $12, 968.71 $13, 266.49 $13, 589.55 $13, 591.41 4.1.34 4.1.48 4.2.20 4.2.34 4.2.48 202.5 million 329.74 grams 1/4 ln x - 3 ln x - 1/2 ln (1 + x) - 1/2 ln (1 - x) ln a (a) C(10) = 0.322 grams per cc (b) t = 90.27 seconds (a) approx. 78.89% (b) 662 years old -4 (ex -e-x )2 1 x+3 4.2.60 4.3.30 4.3.34 4.3.40 4.3.48 4.3.52 4.3.54 + 1 x-1 - 2 x+1 y = -x + 1 g (t) = e-t (t2 - 4t + 2) f (x) = f (x) 2 2x+1 + 3 1-3x f (x) = f (x) -3 + 1 2x-5 + 20 6x-5 4.4.10 always decreasing, no rel. maximum not minimum; conc. downwards for t < - ln 3/2 -0.549; conc. upwards for t > -(ln 3)/2 -0.549; (-(ln 3)/2, 1) is an inection point; y = 2 and y = 0 are horizontal asymptotes; curve crosses (0, 1/2). 4.4.20 abs. maximum (e, e- 1),(e3/2 , 2e3 ) is an inection point 3/2 4.4.24 (a) see graphic (nd y -intercept; and derivative (always positive) and behavior at t +) (b) P (0) = 4 million (c) P (50) = 9.3051 million 20 (d) limt+ P (t) = 2+0 = 10 million 4.4.38 4.4.46 t = 138.89 years (a) P (0) = 220, 000 (b) t = 5, P (5) 225, 760 (c) limt+ P (t) = 70, 000 End. ...
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This note was uploaded on 06/26/2009 for the course MATH 118x taught by Professor Vorel during the Fall '07 term at USC.

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hw4_answers - Instructor Prof Doyoon Kim TA Diogo Bessam...

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