HW Solution 2

# HW Solution 2 - STAT430 Summer 2009 Hui Nie STAT 430...

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STAT430 Summer 2009 Hui Nie STAT 430 Solution 2 Page 50 12. (a) The number of students that take one of three language classes is 28+26+16-12-4-6+2=50 The probability that the randomly chosen student does not take any of three language classes is (100-50)/100=0.5 (b) The number of students that take only one class is 50-12-4-6+2*2=32 Therefore, the corresponding probability is 32/100=0.32 (c) 50 100 149 1/ 22 198 ⎛⎞ ⎛ ⎞ −= ⎜⎟ ⎜ ⎟ ⎝⎠ ⎝ ⎠ 15. (a) 3 41 3 5 2 / 1.98*10 15 5 ⎛ ⎞⎛ ⎞ = ⎜ ⎟⎜ ⎟ ⎝ ⎠⎝ ⎠ (b) 3 13 4 12 4 52 / 0.423 12 31 5 ⎛⎞ ⎛ ⎞ = ⎜⎟ ⎜ ⎟ ⎝⎠ ⎝ ⎠ (c) 2 13 4 11 4 52 / 0.0475 2211 5 ⎛⎞⎛ ⎞ = ⎜⎟⎜ ⎟ ⎝⎠⎝ ⎠ (d) 2 13 4 12 4 52 / 0.0211 13 21 5 = (e) 4 13 4 48 52 / 2.4*10 14 1 5 = 25. 1 42 6 () * 36 36 n n PE = 1 11 6 * 0 . 4 36 36 n n nn ∞∞ == ∑∑ Page 102 3.14 (a) 5779 3 5 12 14 16 18 768 = (b) 4 5779 1 0 5 2 12 14 16 18 384 = 3.19 (a) ( | ) ( ) 0.48*0.38 ( | ) 0.443 ( | ) ( ) ( | ) ( ) 0.37*0.62 pAWPW PW A PAWPW PAMPM ++ = 1

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STAT430 Summer 2009 Hui Nie (b) ( ) 0.48*0.38 0.37*0.62 0.4118 PA == + = 3.26 ( | ) ( ) 0.05 (|) ( | ) ( ) ( | ) ( ) 0.05 0.0025(1 ) cc PC M PM p PM C PC M PM PC M PM p p == + +− Therefore, if there are an equal number of males and females, P(M|C)=20/21.
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## This note was uploaded on 06/28/2009 for the course STAT 430 taught by Professor Krieger during the Summer '08 term at UPenn.

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HW Solution 2 - STAT430 Summer 2009 Hui Nie STAT 430...

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