# HW 7 - Kapoor (mk9499) oldhomework 07 Turner (60230) 1 This...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Kapoor (mk9499) oldhomework 07 Turner (60230) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Through what potential difference would an electron need to be accelerated for it to achieve a speed of 4 . 9 % of the speed of light (2 . 99792 10 8 m / s), starting from rest? Correct answer: 613 . 454 V. Explanation: Let : s = 4 . 9% = 0 . 049 , c = 2 . 99792 10 8 m / s , m e = 9 . 10939 10- 31 kg , and q e = 1 . 60218 10- 19 C . The speed of the electron is v = 0 . 049 c = 0 . 049 ( 2 . 99792 10 8 m / s ) = 1 . 46898 10 7 m / s , By conservation of energy 1 2 m e v 2 =- (- q e ) V V = m e v 2 2 q e = ( 9 . 10939 10- 31 kg ) ( 1 . 46898 10 7 m / s ) 2 2 (1 . 60218 10- 19 C) = 613 . 454 V . 002 (part 1 of 3) 10.0 points Consider two concentric spherical conducting shells. The smaller shell has radius a = 0 . 5 m and charge 3 C on it, while the larger shell has radius b = 3 a and charge 15 C on it. Assume that the electric potential V at is zero. The Coulomb constant is 8 . 98755 10 9 N m 2 / C 2 . b = 3a a #1 #2 P q 1 q 2 O Determine the electric field E at P, where the distance OP = 2 a . Correct answer: 26962 . 7 N / C. Explanation: Let : a = 0 . 5 m , q 1 = 3 C = 3 10- 6 C , q 2 = 15 C = 1 . 5 10- 5 C , and k = 8 . 98755 10 9 N m 2 / C 2 . Set up a Gaussian surface of radius r = 2 a between the shells. Due to symmetry, the electric field is constant over the surface of the sphere, so the flux is simply = E A . The enclosed charge is q 1 . From Gausss Law, = Q encl E 4 r 2 = q 1 , and r = 2 a , so E = q 1 4 (2 a ) 2 = k q 1 4 a 2 = ( 8 . 98755 10 9 N m 2 / C 2 ) 3 10- 6 C 4 (0 . 5 m) 2 = 26962 . 7 N / C . 003 (part 2 of 3) 10.0 points Find the electric potential V at point P . 1. 1 4 parenleftBig q 1 3 a + q 2 2 a parenrightBig 2. 1 4 parenleftbigg q 1 + q 2 3 a parenrightbigg 3. 1 4 parenleftbigg q 1 + q 2 2 a parenrightbigg Kapoor (mk9499) oldhomework 07 Turner (60230) 2 4. 1 4 parenleftBig q 1 2 a + q 2 a parenrightBig 5. 1 4 parenleftbigg q 1 + q 2 a parenrightbigg 6. 1 4 parenleftBig q 1 2 a + q 2 3 a parenrightBig correct 7....
View Full Document

## This note was uploaded on 06/28/2009 for the course PHY 303L taught by Professor Turner during the Fall '08 term at University of Texas at Austin.

### Page1 / 6

HW 7 - Kapoor (mk9499) oldhomework 07 Turner (60230) 1 This...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online