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16 - Kapoor(mk9499 – oldhomework 16 – Turner –(60230...

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Unformatted text preview: Kapoor (mk9499) – oldhomework 16 – Turner – (60230) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points A 156 Ω lamp, a 27 Ω electric heater, and a 41 Ω fan are connected in parallel across a 119 V line. What total current is supplied to the cir- cuit? Correct answer: 8 . 07267 A. Explanation: Let : R 1 = 156 Ω , R 2 = 27 Ω , R 3 = 41 Ω , and V = 119 V . For the parallel circuit, 1 R = 1 R 1 + 1 R 2 + 1 R 3 = R 1 R 2 + R 2 R 3 + R 3 R 1 R 1 R 2 R 3 R = R 1 R 2 R 3 R 1 R 2 + R 2 R 3 + R 3 R 1 R 1 R 2 + R 2 R 3 + R 3 R 1 = (156 Ω) (27 Ω) + (27 Ω) (41 Ω) + (41 Ω) (156 Ω) = 11715 Ω 2 , so R = (156 Ω) (27 Ω) (41 Ω) 11715 Ω 2 = 14 . 7411 Ω and I = V R = 119 V 14 . 7411 Ω = 8 . 07267 A . 002 (part 2 of 4) 10.0 points What is the voltage across the fan? Correct answer: 119 V. Explanation: Because the circuit elements are connected in parallel, the voltage across the fan is the same as that across the whole circuit. 003 (part 3 of 4) 10.0 points What is the current in the lamp? Correct answer: 0 . 762821 A. Explanation: The voltage is the same in all 3 appliances, so the current through the lamp is I 1 = V R 1 = 119 V 156 Ω = . 762821 A . 004 (part 4 of 4) 10.0 points What power is expended in the heater? Correct answer: 524 . 481 W. Explanation: The power consumed by the heater is P 2 = V 2 R 2 = (119 V) 2 27 Ω = 524 . 481 W . 005 (part 1 of 4) 10.0 points A particle of mass m and charge q starts from rest at the origin (point A in the figure below). E B A C G X Y B There is a uniform electric field vector E in the positive y-direction and a uniform magnetic field vector B directed towards the reader. It can be shown that the path is a cycloid whose radius of curvature at the top point is twice the y-coordinate at that level. What is the relation between kinetic energy of the charge at points A and B ?...
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16 - Kapoor(mk9499 – oldhomework 16 – Turner –(60230...

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