26 - Kapoor(mk9499 – homework26 – Turner –(60230 1...

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Unformatted text preview: Kapoor (mk9499) – homework26 – Turner – (60230) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 3) 10.0 points A metal strip 2 cm wide and 0 . 15 cm thick carries a current of 30 A in a uniform magnetic field of 1 T. The Hall voltage is measured to be 4 . 32 μ V. The charge on an electron is 1 . 6 × 10- 19 C. vector B 2 cm . 15 cm I a b Calculate the drift velocity of the electrons in the strip. Correct answer: 0 . 216 mm / s. Explanation: Let : V H = 4 . 32 μ V = 4 . 32 × 10- 6 V , B = 1 T , and w = 2 cm = 0 . 02 m . The Hall voltage as a function of the drift velocity of the electrons in the strip is V H = v d B w , so v d = V H B w = 4 . 32 × 10- 6 V (1 T) (0 . 02 m) · 10 3 mm 1 m = . 216 mm / s . 002 (part 2 of 3) 10.0 points The charge on the electron is 1 . 6 × 10- 19 C. Find the number density of the charge car- riers in the strip. Correct answer: 2 . 89352 × 10 28 m- 3 . Explanation: Let : I = 30 A , t = 0 . 15 cm = 0 . 0015 m , and q = 1 . 6 × 10- 19 C . The current is I = n A q v d n = I A q v d = I w t q v d = 30 A (0 . 02 m) (0 . 0015 m) × 1 (1 . 6 × 10- 19 C) (0 . 000216 m / s) = 2 . 89352 × 10 28 m- 3 ....
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This note was uploaded on 06/28/2009 for the course PHY 303L taught by Professor Turner during the Fall '08 term at University of Texas.

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26 - Kapoor(mk9499 – homework26 – Turner –(60230 1...

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