# 23 - Kapoor(mk9499 oldhomework 23 Turner(60230 This...

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Kapoor (mk9499) – oldhomework 23 – Turner – (60230) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 (part 1 oF 4) 10.0 points A long solenoid carries a current oF 30 A . Another coil (oF larger diameter than the solenoid) is coaxial with the center oF the solenoid, as in the fgure below. The permeability oF Free space is 4 π × 10 7 T m / A. 5 m 1 m Outside solenoid has 150 turns Inside solenoid has 7100 turns 12 cm 2 cm ±ind the magnetic feld in the solenoid. Correct answer: 0 . 0535327 T. Explanation: 2 1 Outside solenoid has N 1 turns Inside solenoid has N 2 turns A 1 A 2 Let : N 2 = 7100 , 2 = 5 m , I 2 = 30 A , and μ 0 = 4 π × 10 7 T m / A . Basic Concepts: Mutual Inductance: M 21 = N 1 Φ 21 I 2 = N 2 Φ 12 I 1 = M 12 . (1) Solution: As in the fgure, iF the solenoid carries a current I 2 , then the magnetic feld is given by B 2 = μ 0 N 2 I 2 2 (2) = (4 π × 10 7 T m / A) (7100) (30 A) (5 m) = 0 . 0535327 T . 002 (part 2 oF 4) 10.0 points ±ind the magnetic ²ux Φ 12 through the cross- sectional area oF the large circular coil due to the 30 A current in the solenoid. Correct answer: 6 . 72712 × 10 - 5 T m 2 . Explanation: Let : r 1 = 12 cm = 0 . 12 m and r 2 = 2 cm = 0 . 02 m , A 1 = π r 1 2 = π (0 . 12 m) 2 = 0 . 0452389 m 2 and A 2 = π r 2 2 = π (0 . 02 m) 2 = 0 . 00125664 m 2 .

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23 - Kapoor(mk9499 oldhomework 23 Turner(60230 This...

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