23 - Kapoor (mk9499) oldhomework 23 Turner (60230) 1 This...

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Unformatted text preview: Kapoor (mk9499) oldhomework 23 Turner (60230) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 4) 10.0 points A long solenoid carries a current of 30 A . Another coil (of larger diameter than the solenoid) is coaxial with the center of the solenoid, as in the figure below. The permeability of free space is 4 10 7 T m / A. 5 m 1 m Outside solenoid has 150 turns Inside solenoid has 7100 turns 12 cm 2 cm Find the magnetic field in the solenoid. Correct answer: 0 . 0535327 T. Explanation: 2 1 Outside solenoid has N 1 turns Inside solenoid has N 2 turns A 1 A 2 Let : N 2 = 7100 , 2 = 5 m , I 2 = 30 A , and = 4 10 7 T m / A . Basic Concepts: Mutual Inductance: M 21 = N 1 21 I 2 = N 2 12 I 1 = M 12 . (1) Solution: As in the figure, if the solenoid carries a current I 2 , then the magnetic field is given by B 2 = N 2 I 2 2 (2) = (4 10 7 T m / A) (7100) (30 A) (5 m) = . 0535327 T . 002 (part 2 of 4) 10.0 points Find the magnetic flux 12 through the cross- sectional area of the large circular coil due to the 30 A current in the solenoid. Correct answer: 6 . 72712 10- 5 T m 2 . Explanation: Let : r 1 = 12 cm = 0 . 12 m and r 2 = 2 cm = 0 . 02 m , A 1 = r 1 2 = (0 . 12 m) 2 = 0 . 0452389 m 2 and A 2 = r 2 2 = (0 . 02 m) 2 = 0 . 00125664 m 2 ....
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23 - Kapoor (mk9499) oldhomework 23 Turner (60230) 1 This...

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