28 - Kapoor (mk9499) oldhomework 28 Turner (60230) This...

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Kapoor (mk9499) – oldhomework 28 – Turner – (60230) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 (part 1 oF 2) 10.0 points A resistance R and a 1 . 8 H inductance are in series across a 55 Hz AC voltage. The voltage across the resistor is 40 V and the voltage across the inductor is 60 V. What is the resistance R ? Correct answer: 414 . 69 Ω. Explanation: Let : L = 1 . 8 H , f = 55 Hz , V R = 40 V , and V L = 60 V . The potential di±erence across an inductor is V L = I X L = I 2 π f L and the potential di±erence across a resistor is V R = I R. Thus we have V R V L = I R I 2 π f L = R 2 π f L , so the resistance is R = V R V L 2 π f L = p 40 V 60 V P 2 π (55 Hz) (1 . 8 H) = 414 . 69 Ω . 002 (part 2 oF 2) 10.0 points What is the AC input voltage? Correct answer: 72 . 111 V.
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This note was uploaded on 06/28/2009 for the course PHY 303L taught by Professor Turner during the Fall '08 term at University of Texas at Austin.

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28 - Kapoor (mk9499) oldhomework 28 Turner (60230) This...

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