31 - Kapoor (mk9499) homework31 Turner (60230) 1 This...

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Unformatted text preview: Kapoor (mk9499) homework31 Turner (60230) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A 0 . 3163 A current is charging a capacitor that has circular plates, 13 . 99 cm in radius. The plate separation is 4 . 55 mm. The permitivity or free space is 8 . 85 10- 12 and the permeability of free space is 1 . 25664 10- 6 T m / A. What is the time rate of increase of electric field between the plates? Correct answer: 5 . 8126 10 11 V / m s. Explanation: Let : I = 0 . 3163 A , r = 13 . 99 cm = 0 . 1399 m , A = r 2 = 0 . 0614873 m 2 , and = 8 . 85 10- 12 . Let E be the flux of the electric field, defined as E = integraldisplay vector E d vector A . Thus d E dt = d dt ( E A ) = I Time rate of increase of electric field between the plates is P = d E dt = I A = . 3163 A (8 . 85 10- 12 )(0 . 0614873 m 2 ) = 5 . 8126 10 11 V / m s . 002 (part 2 of 2) 10.0 points What is the magnetic field between the plates . 023 m from the center? Correct answer: 7 . 43398 10- 8 T. Explanation: Let : r = 0 . 023 m and = 1 . 25664 10- 6 T m / A . Since contintegraldisplay vector B dvectors = d dt E Then magnetic field, B ,at the distance r from the center between the plates satisfies 2 r B = d dt parenleftbigg Q A r 2 parenrightbigg Hence B = I r 2 A = (0 . 3163 A)(0 . 023 m) 2(0 . 0614873 m 2 ) (1 . 25664 10- 6 T m / A) = 7 . 43398 10- 8 T . 003 10.0 points A sinusoidal voltage is applied directly across a 19 . 43 F capacitor. The frequency of the source is 4 . 13 kHz, and the voltage amplitude is 13 . 5 V. Find the maximum value of the displace- ment current in the capacitor. Correct answer: 6 . 8067 A. Explanation: Let : C = 19 . 43 F = 1 . 943 10- 5 F , f = 4 . 13 kHz = 4130 Hz , and V max = 13 . 5 V ....
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31 - Kapoor (mk9499) homework31 Turner (60230) 1 This...

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