This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Kapoor (mk9499) homework33 Turner (60230) 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points The reflecting surfaces of two intersecting flat mirrors are at an angle of 53 , as shown in the figure. A light ray strikes the horizontal mirror at an angle of 54 with respect to the mirrors surface. 53 54 Figure is not drawn to scale. Calculate the angle . Correct answer: 74 . Explanation: Basic Concept: incident = reflected Solution: 1 2 Figure is to scale. The sum of the angles in a triangle is 180 . In the triangle on the left we have angles , 180  1 2 , and 180  2 2 , so 180 = + 180  1 2 + 180  2 2 , or 1 + 2 = 2 . (1) In the triangle on the right we have angles 1 , 2 , and . 180 = 1 + 2 + , so 1 + 2 = 180  . (2) Combining Eq. 1 and 2, we have = 180  2 = 180  2 (53 ) = 74 . As a matter of interest, in the upperhalf of the figure the angles (clockwise) in the triangles from left to right are 36 , 36 , and 108 ; 72 , 37 , and 71 ; 109 , 17 , and 54 ; 126 , 17 , and 37 ; and in the lowerhalf of the figure the angles (counterclockwise) in the triangles from left to right are 17 , 17 , and 146 ; 34 , 37 , and 109 ; 71 , 36 , and 73 ; 107 , 36 , and 37 . 002 (part 1 of 2) 10.0 points Consider the case in which light ray A is in cident on mirror 1 , as shown in the figure. The reflected ray is incident on mirror 2 and subsequently reflected as ray B. Let the an gle of incidence (with respect to the normal) on mirror 1 be A = 57 and the point of incidence be located 20 cm from the edge of contact between the two mirrors. 90 x A B mirror 1 mirror 2 A B Kapoor (mk9499) homework33 Turner (60230) 2 What is the angle of the reflection of ray B (with respect to the normal) on mirror 2 ? Correct answer: 33 . Explanation: If the angle of the incident ray A is A , the angle of reflection must also be A . Since the mirrors are perpendicular to each other, angle B is equal to 90  A B = 90  A = 90  57 = 33 ....
View
Full
Document
This note was uploaded on 06/28/2009 for the course PHY 303L taught by Professor Turner during the Fall '08 term at University of Texas at Austin.
 Fall '08
 Turner
 Physics, Work

Click to edit the document details