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# 32 - Kapoor(mk9499 – oldhomework 32 – Turner –(60230...

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Unformatted text preview: Kapoor (mk9499) – oldhomework 32 – Turner – (60230) 1 This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 6) 10.0 points Hint: The convergent mirror in this problem is a specific part of a lens/mirror system so the object in this mirror may be either real or virtual. Construct a ray diagram. A virtual object is located to the right of a convergent mirror. The object’s distance from the mirror and its focal length are shown in the figure below. 13 7 f f The image is 1. real, erect, and smaller. correct 2. real, inverted, and smaller. 3. real, inverted, and larger. 4. virtual, erect, and larger. 5. virtual, erect, and smaller. 6. virtual, inverted, and larger. 7. real, erect, and larger. 8. virtual, inverted, and smaller. Explanation: 1 p + 1 q = 1 f m = h ′ h =- q p Concave Mirror f > ∞ >p> f f <q < ∞ >m>-∞ f >p>-∞ <q < ∞ >m> 1 >p>-∞ <q < f 1 >m> 002 (part 2 of 6) 10.0 points The image distance is 1.- 13 8 f . 2. 19 9 f . 3. 13 20 f . correct 4.- 10 3 f . 5. 5 2 f . 6. 17 9 f . 7.- 16 7 f . 8.- 15 8 f . 9. 19 27 f . 10. 11 6 f . Explanation: Kapoor (mk9499) – oldhomework 32 – Turner – (60230) 2- 13 7 f f p q 13 20 f 1 p + 1 q = 1 f , where 0 < f for a convergent mirror. 1 q =- 1 p + 1 f =- (- 7) 13 f + 1 f =- (- 7) + (13) 13 f = 20 13 f q = 13 20 f . 003 (part 3 of 6) 10.0 points The magnification is 1....
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32 - Kapoor(mk9499 – oldhomework 32 – Turner –(60230...

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