# 33 - Kapoor(mk9499 – oldhomework 33 – Turner –(60230...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Kapoor (mk9499) – oldhomework 33 – Turner – (60230) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points A convergent lens has a focal length of 14 . 5 cm . The object distance is 21 . 6 cm . q h ′ p h f f Scale: 10 cm = Find the distance of the image from the center of the lens. Correct answer: 44 . 1127 cm. Explanation: 1 p + 1 q = 1 f M = h ′ h =- q p Convergent Lens f > ∞ >p> f f <q < ∞ >M >-∞ Note: The focal length for a convergent lens is positive, f = 14 . 5 cm. Solution: Substituting these values into the lens equation q = 1 1 f- 1 p = 1 1 (14 . 5 cm)- 1 (21 . 6 cm) = 44 . 1127 cm . 002 (part 2 of 2) 10.0 points Find the magnification. Correct answer:- 2 . 04225. Explanation: M =- q p =- (44 . 1127 cm) (21 . 6 cm) =- 2 . 04225 . 003 (part 1 of 2) 10.0 points A divergent lens has a focal length of 30 cm . The object distance is 12 cm ....
View Full Document

{[ snackBarMessage ]}

### Page1 / 4

33 - Kapoor(mk9499 – oldhomework 33 – Turner –(60230...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online