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Unformatted text preview: Kapoor (mk9499) – oldhomework 36 – Turner – (60230) 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 3) 10.0 points A standard setup of the double slit experiment as shown in the sketch. The distance between the two slits is d , the wave length of the incident wave is λ , the distance between the slits and the screen is L . A point on the screen is specified by its ycoordinate, or the corresponding angle θ . y L d S 1 S 2 θ viewing screen θ δ At the fourth minimum on the screen, (i) φ , the phase angle difference of the two rays from slit S 1 and slit S 2 , and (ii) δ , the corresponding path difference are given by 1. φ = 6 π and δ = 6 λ . 2. φ = 7 π and δ = 7 2 λ . correct 3. φ = 8 π and δ = 8 λ . 4. φ = 4 π and δ = 2 λ . 5. φ = 5 π and δ = 5 λ . 6. φ = 6 π and δ = 3 λ . 7. φ = 5 π and δ = 5 2 λ . 8. φ = 4 π and δ = 4 λ . 9. φ = 7 π and δ = 7 λ . 10. φ = 8 π and δ = 4 λ . Explanation: In general, the phase angle difference for minima is given by φ = (2 n + 1) π, with n = 0 , 1 , 2 ··· . The fourth minimum corresponds to n = 3, so φ = 7 π . The corresponding path difference is given by δ = parenleftbigg λ 2 π parenrightbigg φ = 7 2 λ . 002 (part 2 of 3) 10.0 points What is the vertical distance y for the first maximum (which is adjacent to the central maximum)? Use the small angle approxima tion. 1. y = λ d L . 2. y = 2 d L λ . 3. y = 2 λ L d . 4. y = 2 λ d L . 5. y = d L 2 λ . 6. y = d L λ . 7. y = λ L 2 d . 8. y = λ L d . correct 9. y = λ d 2 L . 10. y = λ . Explanation: The first maximum occurs when the path difference is λ , so θ = λ d = y L or y = λ L d . 003 (part 3 of 3) 10.0 points Kapoor (mk9499) – oldhomework 36 – Turner – (60230) 2 Find the minimum positive θ value such that I I = 1 4 , where I and I are the intensities of light at 0 ◦ and at θ , respectively. Use the small angle approximation. 1. θ = d 3 λ . 2. θ = 5 d 24 λ . 3. θ = λ 8 d . 4. θ = λ 3 d . correct 5. θ = λ 6 d ....
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 Fall '08
 Turner
 Physics, Work, Wavelength, Doubleslit experiment, Thomas Young, phase angle difference, 0.0013 m

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