quiz_solutions11

Fundamentals of Physics, (Chapters 21- 44) (Volume 2)

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PY212 Solutions Quiz 11 The distance between adjacent rulings is d = 25.0 mm/9000 = 0.002778 mm = 2.778 μ m. (a) Let ( ) sin 0, 1, 2, d m m θ = λ = ± ± K . Since | m | λ / d > 1 for | m | 5, the largest value of corresponds to | m | = 4, which yields ( ) . 5 . 66 m 10 778 . 2 ) m 10 637 ( 4 sin / sin o 6 9 1 1 = × × = = d m λ (b) The second largest value of corresponds to | m | = 3, which yields ( ) . 5 . 43 m 10 778 . 2 ) m 10 637 ( 3 sin / sin o 6 9 1 1 = × × = =
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Unformatted text preview: − d m (c) The third largest value of corresponds to | m | = 2, which yields ( ) . 3 . 27 m 10 778 . 2 ) m 10 637 ( 2 sin / sin o 6 9 1 1 = × × = = − − − − d m (d) The maxima we have here are numbered by m = –4, –3, –2, –1, 0, 1, 2, 3, 4. Thus, there are 9 maxima in total....
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