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**Unformatted text preview: **t = π / 6 and t = 5 / 6. The problem states that the emf is increasing, so the slope of V must be positive at time t . The slope is given by the derivative of V ( t ): ) cos( ) ( max t V t V dt d = For t = / 6 we obtain cos( t ) > 0, and for t = 5 / 6 we get cos( t ) < 0. Evidently, the right solution is t = / 6. To find the current at this time, we simple substitute it into Eq. 31-52: A. 827 . ) 2 / 6 / sin( ) A 955 . ( ) sin( ) ( − = − = − = π t I t i L Hence, the current is 0.827 A at that moment....

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