{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

quiz_solutions08

# Fundamentals of Physics, (Chapters 21- 44) (Volume 2)

This preview shows pages 1–2. Sign up to view the full content.

PY212 Solutions Quiz 8 This problem can be solved in two ways: assuming R is small (valid assumption) or doing it exactly. We shall first show here the approximation. We do not have an equation for the current as a function of time, but we do have the charge; Eq. 31-25: ( ) ( ) φ ω + = t Qe t q L Rt cos 2 / with /H 2 . 0 2 Ω = L R A and rad/s 1 . 129 1 ) 2 / ( 2 2 2 2 = + = + = ω ω ω A LC L R . The current can be found by take the derivative with respect to time: ( ) ( ) ( ) + + = = φ ω ω φ ω t e t e L R Q dt dq t i L Rt L Rt sin cos 2 2 / 2 / The problem states that initially the current is zero, so we have a situation very similar 1 to Fig. 31-1 with (a) representing the situation at t = 0. According to that figure the charge on the capacitor q ( t ) is at a maximum for t = 0. Hence, from ( ) φ cos 0 Q q = we conclude that φ = 0, and therefore C 10 5 . 0 ) 0 ( 6 × = = q Q . In Fig. 31-1 we see that the current is at a maximum after ¼ of the period. Hence, the current is maximum at ω π 2 4 1 4 1 4

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern