**Unformatted text preview: **now need to check if this critical point is a min/max or inflection. One way is to use the second derivative test (but that is no fun), so we just 2x2 observe that since 2x2 > 1+x2 and 3x2 > 2x2 we have that: f (x) 3x2 - 2x2 >0 1 + x2 notice that this is true no matter if x is positive or negative. So that f is increasing through x = 0, this means that our function must have an inflection point at x = 0. Now that we know all our critical points we can just graph as usual. Doing this problem without making the approximation above is okay t...

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