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Unformatted text preview: Kashif Bari A08218440 Section B09 BICD 100 (Genetics) Homework 1 1. Yellow (Y) Round (R) Green (y) Wrinkled (r) A: Y_R_ x yyrr 50% Yellow Round; 50% Green Round YyRR x yyrr 2 YyRr (Yellow Round): 2 yyRr (Green Round) Genotype of Pea A= YyRR B: Y_R_ x yyrr 100% Yellow Round YYRR x yyrr 4 YyRr (Yellow Round) Genotype of Pea B= YYRR C: Y_R_ x yyrr 25% Yellow Round; 25% Yellow Wrinkled; 25% Green Round; 25% Green Wrinkled YyRr x yyrr 1 YyRr (Yellow Round): 1 yyRr (Green Round): 1 Yyrr (Yellow Wrinkled): 1 yyrr (Green Wrinkled) Genotype of Pea C= YyRr 2. If the fruit fly was of phenotype ‘A’, then that particular allele is dominant relative to another allele. In order to determine if the genotype was homozygous dominant or heterozygous, I would cross the fruit fly with another fruit fly of phenotype ‘a’, which would be homozygous recessive. If the original fruit fly was homozygous dominant, then the phenotype of the offspring would all show that of allele ‘A’. If the original fruit fly was heterozygous, then half progeny would display show that of allele ‘A’....
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- Spring '08
- Genetics, Trigraph, Zygosity