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cee120-spring08-mt1-Moehle-soln

cee120-spring08-mt1-Moehle-soln - CE 120 — Spring 2008...

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Unformatted text preview: CE 120 — Spring 2008 Instructor: J. P. Moehle Name: \j r u 1}, Le, CE 120 — Structural Engineering Mid-Term Examination No. 1 Instructions: II Read these instructions. Do not open the exam until instructed to do so. II Work all problems. Pace yourself so that you have time to work on each problem. Show all relevant work. I Start solutions alongside or immediately following problem statements. If additional space is required, insert additional sheets. Do not show the work for more than one problem on any given sheet of paper. - Organize and write solutions neatly. Points will be taken off for messy solutions. . Indicate units and sign conventions in final solutions. Points will be taken off if units are missing or signs are unclear. o If you have any questions, or need any paper or other materials, walk to the front of the classroom and ask the instructor. Do not raise your hand to get the instructor’s attention, and do not call out questions from your seat. 0 You are allowed only one 8-1/2 by 11 inch sheet of notes for reference. Possible Points Score Problem l 15 __ Problem 2 IS _ Problem 3 15 m Problem 4 30 __ Problem 5 15 neatness, organization 10 TOTAL 1 00 CE 120 — Spring 2008 Exam 1 Problem 1 - Determine whether the structures shown are stable or not. For those that are stable, further classify them as being determinate or indeterminate. (a) Tree-1L M a fiféme If») fifth-f <——T F" 5” = i 31‘?ka I degrfe i‘ndugrryfi/Aafé 0’) m : 15’ r. CE 120 — Spring 2008 Exam 1 Problem 2 —'For the truss shown, calculate forces in selected members. (21) Find the force in member jg. $30k 5 12%: r: F "l 3’ a 51‘» , ,2: l Elfin £10K .. “T" "‘15 5‘73) ‘" é?n/ {’k’fima‘a) (b) Find the force in member Cd. g Cg Mb :—-0 (30")(éo') + Fed (50’) '50 ’5 {’25 [4‘ FCC}, = “’ £353 3"; kch $ 30/2“ ,1 {id 3 Q5) ‘4 Cmva/wap/m) CE 120 — Spring 2008 Exam 1 b- 5, w 101 ' Problem 3 -~ For the frame structure shown: Zkl d e (a) Find the verticai and horizontal reactions at point b. c T Om mm m: (2%: 0 mm mm L4 vb vs 2 . s t" l» J t a b On F {5 Q o 79 CL of '- C; H 74>; and it; 2 Ma = o a [9 , .. M“ J“ _ hiad "” D If i g \,_/ ' H19 : O - - ' - TM (b) Fmd the shear 111 member de Just to the r1ght of member ad. (“3) t W (e) 011 top of the outline of the undeformed frame below right, sketch the deflected shape. CE 120 — Spring 2008 Exam 1 Problem 4 __ Draw and shear and moment diagrams and the deflected shape for the beam shown. lkif downward lklf upward SK 8k 9 3) V v 4’ 8 70‘ L: +9 We ,rr . f ngd 5! a . 'W Shea!” (5k) (215.) + Efi,{$,) I ”(5")(7.S‘)‘ro - c? . 7 I? H k moment (9 5‘9 fl 5 Léfl/{a % o 5 . — t . deflection W; X5) (5 X23) {SHRED-“,0 L} V36 7- 5’; a lo ' C all/St xL ’1‘ Kb 1‘96 (Ema , o "’ (QCX/O’) + (Slabs? ;0 L9 #29 3 g k CgMC;O «A 109+ (we) o CE 120 — Spring 2008 Exam 1 Problem 5 A cable supports a uniformly distributed load and a concentrated load. It has been designed so the slope is zero at support point a. (a) What is the horizontal reaction at point a? (b) What is the elevation of point e relative to point a (that is, what is the value of y)? {.WWA] 21;”: w /c)( uuuuuuuuuuu 10/ _ I .r M .. If; r l vl‘ O ”l M a. M/%HG=A£& v e r e a is shamanism i Zx/oxf L4 3 I; ? : LEE), ...
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