FAQ-Chap01 - 3 H 3 C H H OH Cl These are correct. All these...

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C C C H 3 C H H H H 3 C H OH H (CH 3 ) 2 CHCH(OH)CH 3 FAQ-Chapter 1 CH 3 CH 2 CH 2 CH 2 CH 3 1. Both of these are OK. CH 3 (CH 2 ) 3 CH 3 2. All of these are OK. (CH 3 ) 2 CHCHCH 3 OH (CH 3 ) 2 CHCHCH 3 OH 3. Which one is correct? O O correct incorrect correct incorrect same angle (120 °) same angle (120 °) 4. How are we supposed to know how many constitutional isomers there are? - Ans) There are no golden rules. You can increase your ability to tell if you figure out all the possible ones by taking practices. Do More Problems! You will be confident. Tests may say how many or may not say depending on questions. Exam questions will be reasonable, though. 5. Please stick with basics when you figure out structures and isomers: Carbon needs four bonds, Oxygen needs two bonds, Nitrogen needs three bonds, Hydrogen needs one bond. CH 3 CHClCH(OH)CH 3 C C CH 3 H 3 C H Cl OH H C C CH 3 H 3 C OH Cl H H C C CH 3 H 3 C OH H H Cl C C CH
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Unformatted text preview: 3 H 3 C H H OH Cl These are correct. All these are the same compounds, and the difference between these is just rotation. Cl C CH 3 C H OH H 3 C H Cl C CH 3 C H OH H 3 C H Cl needs only one bond, and here there are two ---> incorrect C needs four bonds, and here there are three ---> incorrect 6. When you draw condensed formula, cyclic structures (including rings) should show bonds to make rings. Straight chains do not show bonds in the backbone. However, rings have to show bonds (e.g., 1-19.c) C C C C H H H H H H HC HC CH 2 CH 2 correct CH=CHCH 2 CH 2 incorrect These two ends have to meet each other to make a ring, moreover these two don't make enough # of bonds. They make only 3 bonds aroung each carbon. No sense....
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