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UNLV, DEPARTMENT OF MECHANICAL ENGINEERING
MEG 242, Spring 2009, FIRST TEST
Closed Book, one page of handwritten notes allowed. Enter the answer for each question
into the space provided. Enter SI units in
all
answer spaces with brackets ( ).
1. (15 points)
A ball is thrown vertically upright with a velocity of 30 m/s at the edge of a
50m cliff. Neglect air resistance.
Determine:
a) the height to which the ball rises.
b) the time to reach the bottom of the cliff.
Answers
(a) v=0 at max. height, thus
v*dv = a*dy
Æ
h = v
0
2
/2g = 45.87 m
insert t into
(b) time to top:
vo – g*t = 0
Æ
t1 = vo/g = 3.06 s
Drop from top height to bottom is s = (45.87+ 50)m = ½*g*t
2
2
t2 = (2*95.87/g)
1/2
= 4.42 s
Version B
h = v
0
2
/2g = 20.38 m
t1 = 20/g = 2.04 s
Drop from top height to bottom is s = (20.38+ 40)m = ½*g*t
2
2
t2 = 3.51 s
Answers:
a)
Max. height =
45.87 m
Version B
hmax
=
20.38 m
(8 pts)
b)
t
bottom
=
7.48
Version B
t
bottom
= 5.55 s
(7pts)
2. (10 points)
A hockey puck sliding on a
horizontal
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This note was uploaded on 07/13/2009 for the course ME a taught by Professor Dr. during the Spring '09 term at University of Nevada, Las Vegas.
 Spring '09
 Dr.

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