chapter13_part2

chapter13_part2 - Chapter 13 Chemical Kinetics Rates of...

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Unformatted text preview: Chapter 13: Chemical Kinetics: Rates of Reactions 596 67. Answer: (a) Reaction (b) (b) Reaction (c) Strategy and Explanation: Assuming everything about the forward reactions in this question is identical except the activation energy, the reaction with the largest E a,forward will be the slowest, and that with the smallest E a,forward will be the fastest. (a) Of the three, the smallest E a,forward is 65 kJ mol –1 . That is reaction (b). (b) Of the three, the largest E a,forward is 85 kJ mol –1 . That is reaction (c). 68. Answer: (a) Reaction (c) (b) Reaction (a) Strategy and Explanation: Assuming everything about the forward reactions in this question is identical except the activation energy, the reaction with the largest E a,forward will be the slowest, and that with the smallest E a,forward will be the fastest. (a) Of the three, the smallest E a,forward is 55 kJ mol –1 . That is reaction (c). (b) Of the three, the largest E a,forward is 175 kJ mol –1 . That is reaction (a). 69. Answer: (a) Reaction (c) (b) Reaction (a) Strategy and Explanation: Assuming everything about the reverse reactions in this question is identical except the activation energy, the reaction with the largest E a,reverse will be the slowest, and that with the smallest E a,reverse will be the fastest. (a) Of the three, the smallest E a,reverse is 15 kJ mol –1 . That is the reverse of reaction (c). (b) Of the three, the largest E a,reverse is 220 kJ mol –1 . That is the reverse of reaction (a). 70. Answer: (a) Reaction (c) (b) Reaction (b) Strategy and Explanation: Assuming everything about the forward reactions in this question is identical except the activation energy, the reaction with the largest E a,reverse will be the slowest, and that with the smallest E a,reverse will be the fastest. (a) Of the three, the smallest E a,reverse is 40 kJ mol –1 . That is the reverse of reaction (c). (b) Of the three, the largest E a,reverse is 138 kJ mol –1 . That is the reverse of reaction (b). 71 . Answer: (a) rate = k[NO][NO 3 ] (b) rate = k[O][O 3 ] (c) rate = [(CH 3 ) 3 CBr] (d) rate = k[HI] 2 Strategy and Explanation: Given the chemical equations of elementary reactions write their rate laws. As described in Section 13.6, the stoichiometric coefficient of a reactant in an elementary equation is the reaction order for that reactant. (a) NO + NO 3 products rate = k[NO] 1 [NO 3 ] 1 (b) O + O 3 products rate = k[O] 1 [O 3 ] 1 (c) (CH 3 ) 3 CBr products rate = [(CH 3 ) 3 CBr] 1 (d) 2 HI products rate = k[HI] 2 72. Answer: (a) rate = k[Cl][ICl] (b) rate = k[Cl][H 2 ] (c) rate = k[NO 2 ] 2 (d) rate = k[cyclopropane] Strategy and Explanation: Given the chemical equations of elementary reactions write their rate laws....
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chapter13_part2 - Chapter 13 Chemical Kinetics Rates of...

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