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chapter17_part2

# chapter17_part2 - 798 Chapter 17 Additional Aqueous...

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Chapter 17: Additional Aqueous Equilibria 799 At equilibrium, the moles of solid that dissolve per liter is: 2.03 g CaSO 4 1 L " 1 mol CaSO 4 136.14 g CaSO 4 = 0.0149 M The stoichiometry of the equation shows that the concentrations of calcium ion and sulfate ion are both the same as the moles of solid that dissolve per liter, 0.0149 M. K sp = [Ca 2+ ][SO 4 2– ] = (0.0149)(0.0149) = 2.22 × 10 –4 57. Answer: K sp = 2.7 × 10 –9 Strategy and Explanation: Follow the method developed in the solution to Question 55. (Assume that the volume is known ± 1mL.) Write the chemical equation and the equilibrium expression for the dissociation of the solute: SrF 2 (s) Sr 2+ + 2 F (aq) K sp = [Sr 2+ ][F ] 2
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