solution06 - 1(a = k t i b k = J J Vin = iR eb = iR k t i =...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
1/ (a) () in t t t in t t in t b in t V RJ k J k J b R k J k b R k V k R k V i k iR e iR V J k b i k J = + + + = = + = + = = Τ = θ / 2 (b) J k s J b R k s RJ k s H t t / ) / ( / ) ( 2 2 + + + = (c) i) When the derivates are set to zero rads 625 . 0 = = = in t in t V Rk k V RJ k J k ii) In the steady the shaft is stationary and the torque produced by the motor is balanced by the torque from the torsional spring. i k k t = = Τ As the shaft is stationary e b is zero and the current is R V i in / = Putting the two together gives the result obtained in (i).
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
iii) rads 625 . 0 5 ) ( lim 5 ) ( ) ( ) ( ) ( 0 = = = = Rk k s sY s s H s X s H s Y t s (d) i) () 4 3 5 . 2 5 ) ( ) ( ) ( ) ( 4 3 5 . 0 ) ( 2 2 + + = = = + + = s s s s s H s V s H s X s s s H c = -0.31250 + 0.35434i, -0.31250 – 0.35434i, 0.625 p = -1.5000 + 1.3229i, -1.5000 - 1.3229i, 0
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 07/16/2009 for the course SYSC 3600 taught by Professor John bryant during the Winter '08 term at Carleton CA.

Page1 / 3

solution06 - 1(a = k t i b k = J J Vin = iR eb = iR k t i =...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online