AME451_HW_Solution_1

AME451_HW_Solution_1 - AME 451 Homework Solution 01 1. 2....

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AME 451 Homework Solution 01 1. 2. 3. 4.
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5. a. Assume when 0, ( ) 0 zt θ == , springs are of the equilibrium length. Let 1 f is the force of the right spring and 2 f is the force of the left spring. 1 sin fk a = 2 2(() s i n ) z t L =− cos c fc b = ± From M I = ±± , we have, 2 21 ( ) cos cos cos c mg f L f a f b mL θθ +− = Then, 222 2 2 cos 2 ( )cos 2 sin cos sin cos cos mgL kLz t kL ka cb mL = ± If is small, sin ,cos 1 ≈≈ 2 2( ) 2 mgL kLz t kL ka cb mL = ± b. Let 1 x is the displacement of the mass
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AME451_HW_Solution_1 - AME 451 Homework Solution 01 1. 2....

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