{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

AME451_HW_Solution_2

# AME451_HW_Solution_2 - AME 451 Homework Solution 02 a qi...

This preview shows pages 1–3. Sign up to view the full content.

AME 451 Homework Solution 02 a. 1 2 i o o dV q q q dt = Since V HA = , 1 o H q R = , 2 o H h q r = Then i H H h q AH R r = ± b. Assume 1 2 H H > , therefore for tank 1, 3 o q is outflow; for tank 2, 3 o q is inflow. For tank 1: 1 1 1 1 3 o o dA H q q q dt = 1 1 1 o H q R = , 1 2 3 3 o H H q R = Then, 1 1 2 1 1 1 1 3 H H H q A H R R = ± For tank 2: 2 2 2 2 3 o o dA H q q q dt + = , 2 2 2 o H q R = Then, 2 1 2 2 2 2 2 3 H H H q A H R R + = ± For tank 3: 3 3 2 4 5 o o o dA H q q q dt = , 3 4 4 o H q R = , 3 5 5 o H q R = Then, 3 3 2 3 3 2 4 5 H H H A H R R R = ± c. Assume the radius of top surface of liquid is r From 2 1 2 h r r H r r = , 1 2 2 r r r h r H = + i o dV q q dt = , o h q R = , h r h H r r r h H r r r r r r h V 2 2 2 2 1 2 3 2 2 1 2 2 2 2 ) ( 3 1 ) ( 3 1 π π π π + + = + + =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document