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Unformatted text preview: . 3 ( ) C K)(100 kg J kg)(390 50 . 3 ( = + = T or C 9 . 28 to three figures. b) Using the result of Example 20.10, the total change in entropy is (making the conversion to Kelvin temperature) K. J 2 . 49 K 273.15 K 302.09 ln K) kg J kg)(4190 800 . ( K 373.15 K 302.09 ln K) kg J kg)(390 50 . 3 ( = + = D S (This result was obtained by keeping even more figures in the intermediate calculation. Rounding the Kelvin temperature to the nearest K 01 . gives the same result....
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This note was uploaded on 07/20/2009 for the course PHYS physics 10 taught by Professor Goatman during the Spring '08 term at The University of British Columbia.
- Spring '08