This preview shows page 1. Sign up to view the full content.
Unformatted text preview: . 3 ( ) C K)(100 kg J kg)(390 50 . 3 ( = + = T or C 9 . 28 to three figures. b) Using the result of Example 20.10, the total change in entropy is (making the conversion to Kelvin temperature) K. J 2 . 49 K 273.15 K 302.09 ln K) kg J kg)(4190 800 . ( K 373.15 K 302.09 ln K) kg J kg)(390 50 . 3 ( = + = D S (This result was obtained by keeping even more figures in the intermediate calculation. Rounding the Kelvin temperature to the nearest K 01 . gives the same result....
View
Full
Document
This note was uploaded on 07/20/2009 for the course PHYS physics 10 taught by Professor Goatman during the Spring '08 term at The University of British Columbia.
 Spring '08
 goatman

Click to edit the document details