BUAD 311T
Solutions to Homework 8
1. JCA Chapter 9A Problem 2
a.
Note that the terms USL (Upper Specification Limit) and UTL (Upper Tolerance Limit)
are equivalent (and so are LTL and LSL—Lower Tolerance Limit and Lower
Specification Limit).
11
.
1
)
003
.
0
(
6
6
=
=
=
σ
C
p
99
.
0
01
.
1
−
−
LTL
UTL
Note that C
p
is not relevant in this situation since the process mean (1.002”) is not centered
at the specification mean (1.00”);
C
pk
is the relevant measure here. Below, C
pk
is calculated
first using the alternate formula given in the lecture notes (it is the formula given in the
textbook), and then with formula that give first in my lecture notes.
{}
33
.
1
,
89
.
0
min
)
003
(.
3
99
.
002
.
1
,
)
003
(.
3
002
.
1
01
.
1
min
3
,
3
min
=
⎭
⎬
⎫
⎩
⎨
⎧
−
−
=
⎭
⎬
⎫
⎩
⎨
⎧
−
−
=
σσ
LTL
X
X
UTL
pk
C
.
= 0.89
Another way to calculate C
pk
(formula given in my notes) is:
()
89
.
0
)
2
.
0
1
(
11
.
1
)
1
(
2
.
0
01
.
0
002
.
0
2
99
.
0
01
.
1
002
.
1
00
.
1
2
Mean
Process
Actual
Mean
Target
=
−
=
−
=
=
=
−
−
=
−
−
=
k
C
C
LSL
USL
k
p
pk
b.
The process is capable of producing the desired quality since Cp =1.11 (a Cp of 1 implies
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 Fall '07
 Vaitsos
 Accounting, Management, UCL, Cpk, fullfare tickets, JCA Chapter 9A, Chapter 9A Problem

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