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Solutions_to_Homework_8_F_08

# Solutions_to_Homework_8_F_08 - BUAD 311T Solutions to...

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BUAD 311T Solutions to Homework 8 1. JCA Chapter 9A Problem 2 a. Note that the terms USL (Upper Specification Limit) and UTL (Upper Tolerance Limit) are equivalent (and so are LTL and LSL—Lower Tolerance Limit and Lower Specification Limit). 11 . 1 ) 003 . 0 ( 6 6 = = = σ C p 99 . 0 01 . 1 LTL UTL Note that C p is not relevant in this situation since the process mean (1.002”) is not centered at the specification mean (1.00”); C pk is the relevant measure here. Below, C pk is calculated first using the alternate formula given in the lecture notes (it is the formula given in the text-book), and then with formula that give first in my lecture notes. {} 33 . 1 , 89 . 0 min ) 003 (. 3 99 . 002 . 1 , ) 003 (. 3 002 . 1 01 . 1 min 3 , 3 min = = = σσ LTL X X UTL pk C . = 0.89 Another way to calculate C pk (formula given in my notes) is: () 89 . 0 ) 2 . 0 1 ( 11 . 1 ) 1 ( 2 . 0 01 . 0 002 . 0 2 99 . 0 01 . 1 002 . 1 00 . 1 2 Mean Process Actual Mean Target = = = = = = = k C C LSL USL k p pk b. The process is capable of producing the desired quality since Cp =1.11 (a Cp of 1 implies

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Solutions_to_Homework_8_F_08 - BUAD 311T Solutions to...

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