Pressure Row 201 1.A fluid sample has a density of 8.99 ×10–2kg/m3and a mass of 150 g. Determine its volume. 1kg150g0.150kg1000gm⎛⎞==⎜⎟⎝⎠mVρ=( )()320.1501.67m8.99 10mV−=×2.Determine the density of a 75 g mass occupying a volume of 6.0 cm3? Two ways to do this. You could convert mass and volume and them calculate 75g0.075kg1000gm3333331m6.0cm0.000006m100cmVWhen a variable is cubed its conversion must be cubed ( )30.07512500kg m0.000006mV=Or you could solve for density in g/cm3and then convert 3312.5g cm6cmmV=12.5g cm100012500kg m×=To do this easier method you’d have to memorize the conversion factor from g/cm3to kg/m3. a. Pgh=()()51000 9.8 272.65 10 PaP×3.A pump sits at the bottom of a fresh water reservoir. The reservoir is 27 m deep. a. Determine the gauge pressure. b. Determine the absolute pressure. b. 0PP gh=+( )()()551 101000 9.8 273.65 10 PaP=×+=
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This note was uploaded on 07/21/2009 for the course PHYSICS 7B taught by Professor Packard during the Spring '08 term at Berkeley.