6610 27 kgamu rhjansen example 2 a gas at 25oc has a

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Unformatted text preview: ansen Example 2 A gas at 25oC has a mass number of 10. a. Determine its molar mass in kg/mol. g 1 kg kg 10 = 0.010 mol 1000 g mol b. Determine the root mean squared velocity of the gas. rms = rms = 3RT M 3(8.31)(298) = 862 m s (0.010) RHJansen Example 3 A gas at 25oC has a mass number of 10. a. Determine the molecular mass in kilograms 1.66 10 - 27 kg 10 amu = 1.66 10 - 26 kg 1 amu b. Determine the root mean squared velocity of the gas. rms = rms = 3kb T m 3(1.38 10 - 23 )(298) = 862 m s - 26 (1.66 10 ) RHJansen Kinetic Energy of a Gas If gas particles have velocity, then they have kinetic energy. Kinetic energy is not a vector, and direction o...
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