solutions-stoichiometry

# solutions-stoichiometry - Stoichiometry overview Recall...

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Stoichiometry overview Recall that in stoichiometry the mole ratio provides a necessary conversion factor: grams (x) moles (x) moles (y) grams (y) molar mass of x molar mass of y mole ratio from balanced equation We can do something similar with solutions: volume (x) moles (x) moles (y) volume (y) mol/L of x mol/L of y mole ratio from balanced equation Read pg. 351-353. Try Q 1-3a.
Ammonium sulfate is manufactured by reacting sulfuric acid with ammonia. What concentration of sulfuric acid is needed to react with 24.4 mL of a 2.20 mol/L ammonia solution if 50.0 mL of sulfuric acid is used? Pg. 353, Question 1 1 mol H 2 SO 4 2 mol NH 3 x # mol H 2 SO 4 = 0.0244 L NH 3 0.0268 4 mol H 2 SO 4 = 2.20 mol NH 3 L NH 3 x H 2 SO 4 (aq) + 2NH 3 (aq) (NH 4 ) 2 SO 4 (aq) Calculate mol H 2 SO 4 , then mol/L = mol/0.0500 L mol/L = 0.0268 4 mol H 2 SO 4 / 0.0500 L =

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Calcium hydroxide is sometimes used in water treatment plants to clarify water for residential use. Calculate the volume of 0.0250 mol/L calcium hydroxide solution that can be completely reacted with 25.0 mL of 0.125 mol/L
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## This note was uploaded on 07/24/2009 for the course CHEM 45434 taught by Professor Michael during the Spring '09 term at Cosumnes River College.

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solutions-stoichiometry - Stoichiometry overview Recall...

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