Spr09RevQuesExamI

Spr09RevQuesExamI - REVIEW QUESTIONS EE-202 Exam I EE-202...

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REVIEW QUESTIONS EE-202 Exam I
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EE-202, Ex 1, page 2 MULTIPLE CHOICE. 1. The mathematical expression of the time function (note that the function continues as an increasing straight line beyond the right edge of the graph) given below is: (a) r ( t ) (b) tu ( t –1) (c) r ( t –1) + u ( t ) (d) ( t –1) u ( t –1) (e) r ( t ) r ( t 1) (f) r ( t ) u ( t 1) (g) Something else 2. Recall that e 2.7 . The Laplace Transform of e t u ( t 2) has the form Ae 2 s s + 1 where A is closest to: (a) 3 (b) 1 (c) 1/3 (d) 1/9 (e) 9 (f) –1/9 (g) Something else 3. The Laplace transform of sin( π 6 t ) δ ( t 1) is A ( s ) e s where A ( s ) is: e s s 2 + ( π 6 ) 2 ( s + 1) 2 + ( π 6 ) 2 4. A partial fraction expansion is given by 8 ( s + 2) 2 ( s + 4) = A s + 2 + B ( s + 2) 2 + C s + 4 Then A is:
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EE-202, Ex 1, page 3 5. The inverse Laplace Transform of 3 s 2 + 4 s + 5 s 2 + 2 s + 5 is K δ ( t ) + Ae t cos(2 t ) + Be t sin(2 t ) u ( t ) where B is: 6. The Laplace Transform of f ( t ) is given as F ( s ) = 1 e s s . Then, the Laplace Transform of df ( t ) dt with f (0 ) = 3 is: (a) –3– e s (b) –1– e s (c) –4– e s (d) –2– e s (e) 1 e s s 2 3 (e) 1 e s s 2 3 s (g) Something else 7. For the same f ( t ) as Problem 6, the Laplace Transform of tf ( t ) is A + B ( s ) e s s 2 where B ( s ) is: (a) 1 (b) –s (c) s (d) 1 s (e) 1+s (f) –(1+s) (g) Something else 8. The circuit given below has differential equation d dt v C ( t ) + 0.5 v C ( t ) = 0.5 v in ( t ) with v in ( t ) = 10 δ ( t ) and v C (0 ) = 5 V. Then v C ( t ) = Ae Bt u ( t ) where A is: (a) 20 (b) 15 (c) 10 (d) 5 (e) 0 (f) –10 (g) Something else
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EE-202, Ex 1, page 4 9. For the circuit given below, the input admittance is K + A s + B where A is: 10. The transfer function of the circuit below is:
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EE-202, Ex 1, page 5 11. The transfer function of the circuit below is: 12. For the circuit below, recall that v C ( t ) = 1 C i C ( q ) dq −∞ t . If I C ( s ) = 0.5 s and V C ( s ) = 1 s 2 + 2 s , then v C (0 ) = : (a) 1 (b) 2 (c) –1 (d) –2 (e) 0.5 (f) –0.5 (g) Something else 13. For the circuit below, the values of R (in ) and C (in F) that make the input admittance Y in ( s ) = 4 2 s + 1 + 4 s 2 s + 1 are: (1) R = 1, C = 4 (2) R = 4, C = 0.25 (3) R = 4, C = 4 (4) R = 0.25, C = 0.25 (5) R = 0.5, C = 2 (6) R = 0.25, C = 4 (7) none of above
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