midterm 1f

midterm 1f - 1. l)(‘t.(.‘l‘lllill(‘ wht-t lwr 1.110...

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Unformatted text preview: 1. l)(‘t.(.‘l‘lllill(‘ wht-t lwr 1.110 fulltm'ing lint'nl' syslvms ;11'¢-(-u|1:«'isl.mll.. and “'50. find 21]] Illt" Htlllllitnlls. (&1). 3?] —+— iZJ'g —+— ;:3; == .$ 2.!‘1 + 4.15.: + 2J'3 + .'I‘_] = U -.'I'] — 2.!‘3 "f- 3.111 I T (1)). "311 - m = l —2.r/1 + 2:12 + m = —2 2.01 — 2!;2 + H; = 0. ® ‘2 '0}? Iliog’j (.2; Q 4 2 f q @461 23/0 o 0 1:3 [230?] “>001 "I '2 e l .2 - _— h” 2 791*31 Lbozwe Mo pongaqut Lama? ‘ern {S m satufion, _—.—-—-_—. n Lt. hu {095 Ojt [o'o‘o‘obgk K40 'gll) fltd‘rdunsn I “‘ O \ FAQ‘IW 'Z 2 l —2 {23+E'3'72‘710 o | o :5 r i o [314px 2,0 G 2 54431—2???) :: I “f o I ( WT / 0 o "’ of“ f5 f3 —1 2 2 2. LN A = 1 —] — . ‘l 5 4 (:1). Calculate the! inverse of A. ~- (lJ). Use your answer to (:1) to find a :5 x 3 matrix B solving the matrix equation (I 1 0 AB = l 0 () . 0 0 -l A" I -1 7. “L ! o o --I Z 7— ‘0 ° UJ—Z'fzj " 1 -l ’l O ‘ ‘3 [21+[: :7 0 I l l I O r .s' 4 our (an-m o e 5 04‘ m-G'Cll aEJoo—vaOoH) >(00120 -/ o I 1 , , 0 [23m] = —é l ' o t o -( 0 0 l -b '7 I “('0 o O { Q 7 -| #— 0 [0 f3 _ ° 0 o o O *I ~—— o'.‘ “f 2 +9 ‘ 1. t +z.o+o-o ‘ 1.0 ,L 2.0+okfl (‘S)-°4/~5)'l’r/'°‘[-s)'l ;(—6)'° + "° MM 4600 H'" A8: “I Z Z 2 lo“ I-EM-nwwom-zm /f6 to “I "t -" f :- 53“ esulz ‘74 “she “1 LL00 ” [333003 I-znu -5-44 6 w (9 ® 2 l l U -l I “.3 U I .2 l l (i (l {l l 3. .1 — _1 _2 l 1 ‘1 and H —v U H U l .3 U U [ [I ll (1 ('l‘hvl'v is 110 mmrl In (-hvt-k this.) (a). Givn :1 dviinitiull of Llu‘ column Hpncv of A. (11). Find :1 basis fur Ilw t'tlllllllll spilt-v of :1. (t'). Givv :1 ('It‘linitiuu 1'01‘ [[10 11:11] 51mm- of :L ((1). Find Lllv 111111 span-.0 of' [1. COM} :: (Mamas d“ Cebu/ms in T2 gay-j “(of (J! {J \ . . "TA-SA CLM Mead] (defining? K t: N L.\ U SQO‘K" 0-: I. S 1 aquafim : 6 ' [F]th '______________. If) G flu lr {38(er In 12%? - 4’s [ x1 x1 In X; I: __ _# )C‘“ 23);; f7 \ Kg 5, X5" , H}; I. J I, [l I U 2 . I ,i zm‘ mw mun-11lan [} (l D 0 Column s, a 7M5 . . uf/Ii , ILL fri- I JLU '11.“.- _. L) _ IL Ur"? M (We «Jam-r9135 ; “IL/«L ..~ 2 p t I e l x} O 4 .— Z I 0 ’ 3 O ._—.. u ' ' ' ' ' ""q -1_ .' . . lmt .5 IH' {110 I111L'ar ll‘illlel'Il‘lllzll nan [rum Jr‘i‘ In :2 gm‘n 1)} saw = f?! 1"] M and lt'l T 1w llu' linvau' tmuslm‘umlmu [rum 1:1." In am gum: h} m = (3" m- —1 Thu linear Lmnslhrrnutitall U is rlnlinuti t0 IH‘ 111v. (10111]MJHH inn: 4. ["(x) : 7‘(.5'(x}). [filteriuinv 11w. matrix of Llu‘ liluvnl' transl})rmaliinn U. (a). (h)- |)vsvrihv I-llt‘ lim'nl' II'EIHHfUl'llléliiUll U gt'nlllvll‘it'ullv. . "'LI r“ . 7(5 Yr : “MI” ‘3 2" row (*2 0 I l 0U ’TXI'T' 43X- r =7 (-0“ {F “VJ'j'J! 1]1[“" --' f " I' I ’[KI_{I.§XE) L33 L2/ L: -rl (H .I , pi i {F 59/” U 13 0 S'necu' “fraizj1(MM6’*!0” ’F r 4”” - l ("(1/1 E Lox {v7 di‘f'iofl ' a; . [My] {é "r Cam/M 0% war“ ‘1 “(7”: J: W I / .- \ U hfl.) C‘JL \(L {le {0.1"th é“ (“9" 07— FL 71 OHC—e / U? U) 50"“1'6 30:41: 0/ PH r r 'l “fay”? m for x = ...
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midterm 1f - 1. l)(‘t.(.‘l‘lllill(‘ wht-t lwr 1.110...

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