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Unformatted text preview: \ \ r
' l Santanav7. '
ﬂ .. (PITIV/M’U./Hejc) /
1“. ProlW‘HRS S‘an Vila P .
ISA; M
.V. v >V l, *' and 4:) from.“ closed 5 den. “nadir/oz: mmié/g Process ; w = _J Pdv 4: MyfIW'J
\ § ~ infra/V, P writ M t. 1.1 la (640‘ Mk. ——'—"———__—————‘___
[W'on ;l\¢ 5* '(‘MT bark) v.= o.oo¢vm’ Hamid from linur rmflle
I): = 4.1— 5" Puma ‘5; V2. 305’?— ”‘7  Thu P1 = MF baw dh’ MM fm95We (P;)."M5}‘é’,
l( {hula Wregfed t (w: '= M. back t; max 541‘
kw” ad from;; I
wk??? 2%: 7652? ‘ ' (\Lq’ 3 $Wk; (1) Linear Reversible Expansion 1 4 2 To find the work done in this process, we can use either the
analytical or the graphical method. oAnalytical Method
\ P = mV + K (where m & K are the straight line
equation constants) 4.2 = 0.004 m + K a (1) 1.4 = 0.02 m +.K 4 (2)
Solving simultaneously gives m =' 175 and K = 4.9
2 2
1412 «J P.dV =J ( 1'75v + 14.9) (W
l 1 at 7 [V2]? + 459 mi)
==87.5 [0.022  0.0042] + 4.9 [0.02 — 0.004]) = 49% ~oe336 + 0.0784) =0.0448 bar m3 4. tofu/H: . ",3 w i
5&4480 N.m (Work done by the Fluid). CMOMI’N wiou. Graphical Method The work is the area under line 1 4 2, that is 12ab1 which is a
trapezoid. Area of the trapezoid 12ab1 = 8 (2a + 1b) >< ab
= $2 (1.4 + 4,2) X (0.02 — 0.004)
0.0AA8 bar m3 = 4A80 N.m (Work done by the Fluid which is the same result obtained from the analytical a“ M solution. tv; .
Midf II (2) Reversible Cooling at Constant Pressure 2 a 3 You will notice that we require V3 to be able to obtain the
work in the process 2 > 3. In the process 3 —* l, the product
of pressure and volume is always constant, so Plvl = Psva e—ﬁ" .o' =Wldj M F’”“’55 V3 ll Plvl/Pa 3 vb I ll (4.2)(0.004)/(1.l+) 0.012 m3 3
‘P.dV S
N
(1. 1 =P [v]: =uP (V3  V2)
=(1.£+)(0.012  0.02) = + 0.0112 bar In3 "II— = g]: 1120 N.m (Work done on the Fluid) tpocHNQ
WM (3) Reversible Compression with PV = Constant 3 4 1 1 hmﬂ
W3_1 = J;an
3 .
PI'V. : l
dV / 1
= Constant T =—Constant [103”,3 V]3
3
=(4,2)(0.001+)( 5.521  [ 4.4231) =  0.01845 bar m3 = $1845 N.m (Work done on the Fluid)
M So, Net work of the cycle =£+480 + 1120 + 1816 =1515 N.m «all: to". 57 1‘: wrkp‘y ﬂuid
t it! SMMJI‘A $‘_ Elk1&1:
A r3834 (Ian'st “r on” (no u! not. A: cw” «5.1L. nutW t d‘. $WIMJ;N I, m ' 1: i’dthM ﬁe wk m Jm‘y W: [NW3.
(Asian; 3‘! M #004” from: {a q rmp'lh ...
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This note was uploaded on 07/26/2009 for the course ENG sem314 taught by Professor Dunno during the Spring '09 term at A.T. Still University.
 Spring '09
 dunno

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