Unformatted text preview: FORCE VECTORS
Cartesian Vectors (3Dimensional Vectors) LEARNING OBJECTIVES Be able to resolve each force into its rectangular components Fx, Fy and Fz. Be able to represent the components of force in terms of the Cartesian unit vectors i, j and k. Be able to determine 3dimensional force resultants using the Cartesian unit vectors. PREREQUISITE KNOWLEDGE Units of measurements. Trigonometry concepts. Vector concepts. RIGHTHANDED COORDINATE SYSTEM A denotes a vector whereas A denotes the magnitude of A RECTANGULAR COMPONENTS OF FORCE VECTOR
A=A +A +A
Magnitude of Ax : Ax = A cos Magnitude of Ay : Magnitude of Az : Ay = A cos Az = A cos The Directional Cosines are Cos = Ax/A Cos = Ay/A Cos = Az/A CARTESIAN UNIT VECTORS
i : the Cartesian unit vectors in xdirection j : the Cartesian unit vectors in ydirection k : the Cartesian unit vectors in zdirection
Z 1 unit 1 unit k j
Y i
X 1 unit 3D FORCE RESULTANTS
FR = F FR = FRx i + FRy j + FRz k FRx = Fx FRy = Fy F = F
R
2 FRz = Fz 2
RX +F 2 RY +F 2 RZ + cos2 + cos2 = 1 cos DIRECTIONAL VECTOR
The directional vector of the resultant force FR is a unit vector, uF, that indicates the direction of FR
FR uF
1 unit FR = F R u F FR FR = ( ) uF = FRX FR i+ FRY FR
2 j+ FRZ FR k ; and
, and are called the coordinate direction angles u F = cos i + cos j + cos k FR = FRX + FRY + FRZ and u F = COS + COS + COS = 1
2 2 2 2 2 EXAMPLE 1 Determine the magnitude FR and the coordinate direction angles of the resultant force FR SOLUTION 1
Resolve F1 (the 75 lb force): F1 = 75[0.0i  (24/25)j + (7/25)k F1 = 72.00j + 21.00k Resolve F2 (the 55 lb force): F2 = 55[(cos30)(cos60)i + (cos30)(sin60)j  (sin30)k] F2 = 23.82i + 41.25j 27.50k FR = F1 + F2 = 23.82i + (41.25 72.00)j + (21.00  27.5)k = 23.82i  30.75j  6.50k SOLUTION 1  continued We know that FR = F1 + F2 = 23.82i 30.75j 6.50k FR = [23.822 + (30.75)2 + (6.5)2]0.5 = 39.43 lb. = cos1(23.82/39.43) = 52.8o; = cos1(30.75/39.43) = 141o; and = cos1(6.50/39.43) = 99.5o EXAMPLE 2
The pole is subjected to force F whose components are Fx=1.5 kN and Fz=1.25 kN. Assume the direction coordinate angle =75o. Determine the magnitudes (F and Fy) of F and Fy. SOLUTION 2
Use Cos2 + cos2 + cos2 = 1 Given Fx=1.5 kN, Fz=1.25 kN, and =75o 1.5 1.25 2 o + cos 75 + =1 F F F = 2.02kN Fy = F cos 75 = 0.523kN 2 2 ...
View
Full Document
 Spring '08
 Buch
 Dot Product, Force, Euclidean vector, Standard basis, cartesian unit vectors

Click to edit the document details