U_-_Relationships_Between_Load__Shear__a

3 draw sfd based on the calculated shear force from

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Unformatted text preview: ased on the calculated shear force from left to right 4. Calculate the bending moment along the member from left to right "Bending moment can be calculated as the area underneath the SFD" 5. Draw BMD based on the calculated bending moment from left to right EXAMPLE 1 If P = 600 lb, a = 5 ft and b = 7 ft, draw the SFD and BMD Solve for support reactions 600 lb AX SOLUTION 1 R AY 5 ft 7 ft BY MA= 0; RBY(12) 600(5) = 0; R R R = 250 lb SOLUTION 1 -Contd. Draw SFD and BMD 600 lb 5 ft 350 lb 350 lb SFD 250 lb 0 + 5(350) = 1750 lb-ft BMD 7 ft 250 lb 0 lb 1750 7(250) = 0 lb-ft EXAMPLE 2 Draw SFD and BMD for the beam SOLUTION 2 Solve for support reactions AX R AY BY R R MA = 0; RBY(20) 50(20)(10) 200 = 0; R = 510 lb SOLUTION 2 -Contd. 490 lb 510 lb 490 lb SFD 0 lb 490/5...
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This note was uploaded on 07/26/2009 for the course CE 221 taught by Professor Buch during the Spring '08 term at Michigan State University.

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