Platt, David – Homework 18 – Due: Oct 21 2005, 4:00 am – Inst: Ken Shih
1
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The due time is Central
time.
001
(part 1 of 5) 10 points
The current loop
ABCDA
carries current
I
in the direction indicated in the figure, where
the segments
AB
and
CD
are concentric arcs
with radii
a
and
b
respectively.
a
C
B
b
D
A
O
60
◦
x
y
What is the magnitude of the resultant
magnetic field
k
~
B
k
at the center of curva
ture
O
due to the current segment of arc
CD
?
1.
k
~
B
CD
k
=
μ
0
I
12
1
b
2.
k
~
B
CD
k
=
μ
0
I
6
1
b
3.
k
~
B
CD
k
=
μ
0
I
24
1
b
2
4.
k
~
B
CD
k
=
μ
0
I
6
1
b
2
5.
k
~
B
CD
k
= 0
6.
k
~
B
CD
k
=
μ
0
I
12
1
b
2
7.
k
~
B
CD
k
=
μ
0
I
3
1
b
8.
k
~
B
CD
k
=
μ
0
I
3
1
b
2
9.
k
~
B
CD
k
=
μ
0
I
24
1
b
002
(part 2 of 5) 10 points
What is the direction of the resultant mag
netic field
~
B
at the center of curvature
O
due
to the current segment of arc
CD
?
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 Fall '08
 Turner
 Physics, Work, Magnetic Field, Districts of Vienna, resultant magnetic ﬁeld

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