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Unformatted text preview: Platt, David Homework 22 Due: Oct 31 2005, 4:00 am Inst: Ken Shih 1 This printout should have 8 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points A(n) 0 . 58 m length of wire moves across a 2 . 14 T magnetic field. At what speed would it have to move to induce an EMF of 13 . 1 V? Correct answer: 10 . 5543 m / s. Explanation: Let : = 0 . 58 m , B = 2 . 14 T , and EMF = 13 . 1 V . The induced EMF is V = B l v Thus v = V B l = 13 . 1 V (2 . 14 T)(0 . 58 m) = 10 . 5543 m / s . 002 (part 1 of 1) 10 points A135turn5cmsquarewirecoilrotatesabout a vertical axis at 1210 rev / min. The horizon tal component of the Earths magnetic field at the location of the loop is 2 . 8 10 5 T. B x = 2 . 8 10 5 T B x = 2 . 8 10 5 T 5cm 5 c m 1210 rev / min Calculate the maximum emf induced in the coil by Earths field. Correct answer: 1 . 19742 mV. Explanation: Let : = 5 cm = 0 . 05 m , A = 2 = 25 cm 2 = 0 . 0025 m 2 , = 1210 rev / min , N = 135 turns , and B = 2 . 8 10 5 T . The maximum emf is E max = N AB = (135) ( . 0025 m 2 ) ( 2 . 8 10 5 T ) (1210 rev / min) 2 rad 1rev 1min 60sec 10 3 mV 1 V = 1 . 19742 mV . 003 (part 1 of 2) 10 points The resistance of the rectangular current loop is R , and the metal rod is sliding to the left. The length of the rod is d , while the width of the rails is . Note: a and b are the contact points where the rod touches the rails, and d > . v m R a b B B d What is the magnitude of the induced cur rent around the loop?...
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This note was uploaded on 07/26/2009 for the course PHY 303L taught by Professor Turner during the Fall '08 term at University of Texas at Austin.
 Fall '08
 Turner
 Physics, Work

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