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j90~g block is launched by compressing a spring constant k = 200 N/m a distance of 15 cm. The dng is mounted horizontally, and the surface ectly under it is frictionless. But beyond the ," "ilibrium position of the spring end, the surface >1iS coefficient of friction J-t = 0.27. This frictional ~#rface extends 85 em, followed by a frictionless ~urved rise, as shown in Fig. 8-41. After launch, where does the block finally come to rest? .easure'from the left end of the frictional zone. ttion
of the block when it first encounters point 0) is Ko= !(200 N/m)(0.15 m)2 = ;if we take the zero of gravitational potential y at that level. Crossing the frictional zone, the >}osesenergy LlE = Wnc = -J-tkmg = -(0.27) x
'ergy Il (at 138 CHAPTER 8 Problem
64. The Sun's total power output is 3.85x 1026 W. What is.the associated. rate at which the Sun loses mass? Solution
With the use of Einstein's equation, the power output of the Sun is found to b...
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