# 0xl05 nm1400 kgo16 m 358 ms i 129 kmh i problem

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: in Fig. 8-30. What is the minimum height h at which it can start from rest and still make it around the loop? I:. Solution Problem 29 Solution. From the conservation of mechanical energy (no friction) KA +UA == KB+UB,mgYA = !mv~+mgYB, or v~ = 2g(h - 2R). The condition that the block stay on the track is v~ ~ gR (see the solution to Problem 68 below), so 2g(h - 2R) ~ gR or h ~ 5R/2. Problem .30, A runaway truck lane heads uphill at 300 to the i horizontal. H a 16,000-kg truck goes out of control and enters the lane going 110 km/h, how far along the ramp does it go? Neglect friction. A lal I I I I I B _ olution yi/g >we neglect losses in mechanical energy, -AK = Imv~ = AU = mgy = mgsin 300 Therefore, e == 2. . . 2. = (nO m/3.6 s)2/(9.8 m/s ) = 95;3 m. 1.. I FIGURE 8-30 Problem 32 Solution. 130 CHAPTER 8 Ii Ii Problem 33. Show that the rope in Example 8-6 dw remain , taut all the way to the top of its smaller loop only if a ~ ~. (Note thatthe maximum r~lease angle is 90 for the rope to be taut On the way down.) . Solution :1 'I " I! For the rope to be taut at the top of th...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern